dp问题

//状态：dp[i][j]表示打第i个响指，第j个开关的状态；
#include <iostream>
#include <string.h>
using namespace std;


int dp[102][12];
int n, k;

int main() {

    int num;
    cin >> num;
    for(int l=1;l<=num;++l){

        memset(dp, 0, sizeof(dp));

        cin >> n >> k;

        for (int i = 1; i <= k; ++i) {
            if (i & 1) {
                dp[i][1] = 1;
            }
        }

        for (int j = 2; j <= 11; ++j) {
            int ans = 0;
            for (int i = j; i <= k; ++i) {
                bool temp = true;
                for (int p = 1; p < j; ++p) {
                    if (!dp[i - 1][p]) {
                        temp = false;
                        break;
                    }
                }
                if (temp) {
                    dp[i][j] = !dp[i - 1][j];
                }
                else {
                    dp[i][j] = dp[i - 1][j];
                }
            }
        }
        if (dp[k][n]) {
            cout << "Case " << l << ": ON" << endl;
        }
        else {
            cout << "Case " << l << ": OFF" << endl;
        }
    }
    return 0;
}