2017.11 程序设计基础月考

//********** Specification of FractionSum **********
long long FractionSum(int aaaabbbb, int ccccdddd);
/* PreCondition:
     aaaabbbb和ccccdddd表示分数aaaa/bbbb和cccc/dddd,分子分母最多4位数
   PostCondition:
     计算两个分数之和，返回其最简分数xxxxxxxxyyyyyyyy
*/

//********** Specification of FractionSum **********
long long FractionSum(int aaaabbbb, int ccccdddd) { //TODO: your function definition

}

#include <stdio.h>

int main() {
    int a, b, c, d;
    long long r;
    scanf("%d%d%d%d", &a, &b, &c, &d);
    r = FractionSum(a * 10000 + b, c * 10000 + d);

    printf("%d/%d+%d/%d=%lld/%lld.\n", a, b, c, d,
           r / 100000000, r % 100000000);
    return 0;
}