1366. Brackets

单点时限: 2.0 sec

内存限制: 256 MB

The operation of subtraction is not associative, e.g. (5-2)-1=2, but 5-(2-1)=4, therefore (5-2)-1<>5-(2-1). It implies that the value of the expression of the form 5-2-1 depends on the order of performing subtractions. Usually in lack of brackets we assume that the operations are performed from left to right, i.e. the expression 5-2-1 is equivalent to the expression (5-2)-1.

We are given an expression of the form

x1 +/- x2 +/- … +/- xn,

where each +/- denotes either + (plus) or - (minus), and x1,x2,…,xn denote (pairwise) distinct variables. In an expression of the form

x1-x2-…-xn

we want to insert n-1 pairs of brackets to unambiguously determine the order of performing subtractions and, in the same time, to obtain an expression equivalent to the given one. For example, if we want to obtain an expression equivalent to the expression

x1-x2-x3+x4+x5-x6+x7

we may insert brackets into

x1-x2-x3-x4-x5-x6-x7

as follows:

(((x1-x2)-((x3-x4)-x5))-(x6-x7)).

Note: We are interested only in fully and correctly bracketed expressions. An expression is fully and correctly bracketed when it is

either a single variable,

or an expression of the form (w1-w2), in which w1 and w2 are fully and correctly bracketed expressions.

Informally speaking, we are not interested in expressions containing spare brackets like: (), (xi), ((…)). But the expression x1-(x2-x3) is not fully bracketed because it lacks the outermost brackets.

Task

Write a program which:

1.reads the description of the given expression of the form x1 +/- x2 +/- … +/- xn,

2.computes the number of different ways (modulus 1 000 000 000) in which n-1 pairs of brackets may be inserted into the expression x1-x2-…-xn so as to unambiguously determine the order of performing subtractions and, in the same time, to obtain an expression equivalent to the given one,

3.writes the result.

输入格式

In the first line there is one integer n, 2<=n<=5000. This is the number of variables in the given expression. In each of the following n-1 lines there is one character: + or -. In the i-th line there is the sign appearing between xi-1 and xi in the given expression.

输出格式

In the first line your program should write one integer equal to the number of different ways (modulus 1 000 000 000) in which n-1 pairs of brackets may be inserted into the expression x1-x2-…-xn so as to unambiguously determine the order of performing subtractions and, in the same time, to obtain an expression equivalent to the given one.

样例

Input
7
Output
-
+
+
Input
+
Output
3

0 人解决,2 人已尝试。

0 份提交通过,共有 6 份提交。

9.9 EMB 奖励。

创建: 16 年,11 月前.

修改: 6 年,10 月前.

最后提交: 2 年,3 月前.

来源: POI

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