0 人解决,2 人已尝试。
0 份提交通过,共有 5 份提交。
9.9 EMB 奖励。
单点时限: 2.0 sec
内存限制: 256 MB
Periodic permutation is a simple encryption technique which involves choosing a period, k, and a permutation of the first k numbers. To encrypt a message, split the message into groups of k characters (padding if necessary) and apply the given permutation. Decryption involves taking groups of k characters and performing the inverse permutation. Thus for k = 4, a permutation could be 2431. This would encrypt Mary' to
yMra’ and Maryan' to
yMra?a?n’. Once one knows the permutation, one can apply its inverse to other encrypted messages (cyphertext) to recover the original text (plaintext).
Write a program that will read (plaintext, cyphertext1, cyphertext2) triples, and for each (plaintext, cyphertext1) pair determine whether or not a periodic permutation encryption method has been used. If it has, determine the value of k and the permutation function and apply the reverse permutation to cyphertext2 to recover the corresponding plaintext.
Input will consist of a series of (plaintext, cyphertext1, cyphertext2) triples. Lines will be no more than 80 characters long. The first two strings (of length n) represent the first n characters of the plaintext and cyphertext. There is no implication that n is a multiple of k. The file will be terminated by a line consisting of a single #.
Output will consist of a series of lines, one for each triple in the input. If a permutation cycle has been found, apply the inverse permutation to cyphertext2, padding it if necessary with `?’. If no periodic permutation can be found (with period less than or equal to the length of the plain and cyphertext1 strings) that transforms the plaintext into the cyphertext, then print cyphertext2 unchanged. If more than one periodic permutation could have mapped the plain text to the cyphertext1, then apply the periodic permutation that has the smallest value for k. There will never be more than one shortest permutation function that matches the data.
Mary had a little lamb!! aMyrh daa l tilt ealbm!! hTsii s aetts Foobar blargg No cycle abc bca abcd #
This is a test No cycle cab?d?
0 人解决,2 人已尝试。
0 份提交通过,共有 5 份提交。
9.9 EMB 奖励。