8 人解决，15 人已尝试。
31 份提交通过，共有 63 份提交。
6.6 EMB 奖励。
单点时限: 2.0 sec
内存限制: 256 MB
Design a container, which has two kinds of operation, push and pop.
Push: You should push the given number into the container.
Pop: Please find the middle number of the container. If these is n numbers in container, it will be the (n+1)/2-th num when sort increased. Then pop the number.
The input contains one or more data sets. At first line of each input data set is an integer N (1<= N <= 100000) indicate the number of operations.
Then N lines follows, each line contains a number (0 or 1). “0” means a push operation, it’s followed by an integer E. “1” means a pop operation.
You may assume all the numbers in the input file will be in the range of 32-bit integer.
For each pop operation, you should print the integer popped. Please print “No Element!”, if there is no number to pop. Please print a blank line after each data set.
9 0 10 0 -10 0 5 1 1 0 2 1 1 1 3 0 2 0 1 1
5 -10 2 10 No Element! 1
8 人解决，15 人已尝试。
31 份提交通过，共有 63 份提交。
6.6 EMB 奖励。
创建: 15 年，4 月前.
修改: 7 年，3 月前.
最后提交: 1 年，5 月前.
来源: N/A