写我的笨笨方法
#include<iostream> #include<map> #include<string> #include<cstring> using namespace std; map<char, int>m1; void speakout(int n){ if(n == 0) cout << "-----"; if(n == 1) cout << ".----"; if(n ==2) cout << "..---"; if(n == 3) cout << "...--"; if(n == 4) cout << "....-"; if(n == 5) cout << "....."; if(n == 6) cout << "-...."; if(n == 7) cout << "--..."; if(n == 8) cout << "---.."; if(n ==9) cout << "----."; } int main(){ m1['A'] = 21; m1['B'] = 22; m1['C'] = 23; m1['D'] = 31; m1['E'] = 32; m1['F'] = 33; m1['G'] = 41; m1['H'] = 42; m1['I'] = 43; m1['J'] = 51; m1['K'] = 52; m1['L'] = 53; m1['M'] = 61; m1['N'] = 62; m1['O'] = 63; m1['P'] = 71; m1['Q'] = 72; m1['R'] = 73; m1['S'] = 74; m1['T'] = 81; m1['U'] = 82; m1['V'] = 83; m1['W'] = 91; m1['X'] = 92; m1['Y'] = 93; m1['Z'] = 94; int times; cin >> times; for(int i = 0; i < times; i++){ string str; cin >> str; cout << "case #" << i <<":" << endl; for(int j = 0; j < str.size(); j++){ int k = m1.at(str[j]); int last = k % 10; int first= k / 10; speakout(first); cout << '/'; speakout(last); if(j != str.size()-1) cout << '/'; } cout << endl; } }
试着学会使用常量数组简化程序
using namespace std; const int toint[26]={21,22,23,31,32,33,41,42,43,51,52,53,61,62,63,71,72,73,74,81,82,83,91,92,93,94}; const string tocode[10]={“-----“,”.----“,”..—“,”…–“,”....-“,”.....”,”-....”,”–…”,”—..”,”----.”}; int T; void print(char aa) { int index=toint[aa-‘A’]; cout<<tocode[index/10]; cout<<”/”<>line; int ll=line.length(); int first=1; for(int i=0;i<ll;i++) { if(first) first=0; else cout<<”/”; print(line[i]); } cout<<endl; return; }
int main() { scanf(“%d”,&T); for(int step=0;step<T;step++) { printf(“case #%d:\n”,step); solve(); } return 0; }
#include <bits/stdc++.h> using namespace std; typedef long long ll; string code[10] = {"-----",".----","..---","...--","....-",".....","-....","--...","---..","----.",}; vector <int> stringtoint(string s) { vector <int> res; for (int k = 0; k < s.size(); k++) { int i = s[k] - 65; int first, second; if (i >= 0 && i < 15) { first = i / 3 + 2; second = i % 3 + 1; } else if (i >= 15 && i < 19) { first = 7; second = i - 15 + 1; } else if (i >= 19 && i < 22) { first = 8; second = i - 19 + 1; } else { first = 9; second = i - 22 + 1; } res.push_back(first); res.push_back(second); } return res; } int main(void) { #ifdef LC freopen("input.txt", "r", stdin); freopen("output.txt", "w", stdout); #endif int T, cnt = 0; cin >> T; while (T--) { //1: 输入数据 string s; cin >> s; //2：核心算法 vector <int> tmp = stringtoint(s); //3: 输出结果 cout << "case #" << cnt << ":\n"; cnt++; for (int i = 0; i < tmp.size() - 1; i++) { cout << code[tmp[i]] << "/"; } cout << code[tmp[tmp.size() - 1]]; cout << endl; } return 0; }
写我的笨笨方法
试着学会使用常量数组简化程序
include
using namespace std;
const int toint[26]={21,22,23,31,32,33,41,42,43,51,52,53,61,62,63,71,72,73,74,81,82,83,91,92,93,94};
const string tocode[10]={“-----“,”.----“,”..—“,”…–“,”....-“,”.....”,”-....”,”–…”,”—..”,”----.”};
int T;
void print(char aa)
{
int index=toint[aa-‘A’];
cout<<tocode[index/10];
cout<<”/”<>line;
int ll=line.length();
int first=1;
for(int i=0;i<ll;i++)
{
if(first) first=0; else cout<<”/”;
print(line[i]);
}
cout<<endl;
return;
}
int main()
{
scanf(“%d”,&T);
for(int step=0;step<T;step++)
{
printf(“case #%d:\n”,step);
solve();
}
return 0;
}