int main(){ int m,n; scanf(“%d”,&m); scanf(“%d”,&n); int i; for(i=1; i<=n*m; i++){ if(i % n == 0){ printf(“%d\n”,i); } else printf(“%d “,i); } }
真是一道很9的题啊 顺序输出就能过的东西233333
#include <cstdio> int main() { int m, n; scanf("%i%i", &m, &n); for (int i = 1; i <= m; ++i) { printf("%i", (i - 1) * n + 1); for (int j = 1; j < n; ++j) { printf(" %i", (i - 1) * n + 1 + j); } putchar('\n'); } }
Cirno and aC number ⑨ problem.
#include <stdio.h> int main(void) { int m, n, i, j; scanf("%d%d",&m,&n); for(i=0; i<m; i++) { for(j=0; j<n-1; j++) printf("%d ",i*100+j+1); printf("%d\n",i*100+j+1); } return 0; }
using namespace std; int main() { long int m,n; cin>>m; cin>>n; int i,j; int k=10; for(i=1;i<=m;i++) { for(j=1;j<=n-1;j++){cout<<k++<<” “;} cout<<k++<<endl; }
}
include
int main(){
int m,n;
scanf(“%d”,&m);
scanf(“%d”,&n);
int i;
for(i=1; i<=n*m; i++){
if(i % n == 0){
printf(“%d\n”,i);
}
else printf(“%d “,i);
}
}
真是一道很9的题啊
顺序输出就能过的东西233333
Cirno and aC number ⑨ problem.
include
using namespace std;
int main()
{
long int m,n;
cin>>m;
cin>>n;
int i,j;
int k=10;
for(i=1;i<=m;i++)
{
for(j=1;j<=n-1;j++){cout<<k++<<” “;}
cout<<k++<<endl;
}
}