144 人解决，290 人已尝试。
190 份提交通过，共有 952 份提交。
4.4 EMB 奖励。
单点时限: 2.0 sec
内存限制: 256 MB
The objective of the program you are going to produce is to evaluate boolean expressions as the one shown next:
Expression: ( V | V ) & F & ( F | V )
where V is for True, and F is for False. The expressions may include the following operators: ! for not, & for and, | for or, the use of parenthesis for operations grouping is also allowed. To perform the evaluation of an expression, it will be considered the priority of the operators, the not having the highest, and the or the lowest. The program must yield V or F, as the result for each expression in the input.
The expressions are of a variable length, although will never exceed 2000 symbols. Symbols may be separated by any number of spaces or no spaces at all, therefore, the total length of an expression, as a number of characters, is unknown.
The number of expressions in the input file is variable and will never be greater than 20. Each expression is presented in a new line, as shown below.
For each test expression, print “Expression “ followed by its sequence number, “: ”, and the resulting value of the corresponding test expression. Separate the output for consecutive test expressions with a new line.
Use the same format as that shown in the sample output shown below.
( V | V ) & F & ( F| V) !V | V & V & !F & (F | V ) & (!F | F | !V & V) (F&F|V|!V&!F&!(F|F&V))
Expression 1: F Expression 2: V Expression 3: V
144 人解决，290 人已尝试。
190 份提交通过，共有 952 份提交。
4.4 EMB 奖励。