1272. The Circumference of the Circle

单点时限: 2.0 sec

内存限制: 256 MB

To calculate the circumference of a circle seems to be an easy task - provided you know its diameter. But what if you don’t?

You are given the cartesian coordinates of three non-collinear points in the plane.

Your job is to calculate the circumference of the unique circle that intersects all three points.

输入格式

The input will contain one or more test cases. Each test case consists of one line containing six real numbers x1,y1, x2,y2,x3,y3, representing the coordinates of the three points. The diameter of the circle determined by the three points will never exceed a million. Input is terminated by end of file.

输出格式

For each test case, print one line containing one real number telling the circumference of the circle determined by the three points. The circumference is to be printed accurately rounded to two decimals. The value of pi is approximately 3.141592653589793.

样例

Input
0.0 -0.5 0.5 0.0 0.0 0.5
0.0 0.0 0.0 1.0 1.0 1.0
5.0 5.0 5.0 7.0 4.0 6.0
0.0 0.0 -1.0 7.0 7.0 7.0
50.0 50.0 50.0 70.0 40.0 60.0
0.0 0.0 10.0 0.0 20.0 1.0
0.0 -500000.0 500000.0 0.0 0.0 500000.0
Output
3.14
4.44
6.28
31.42
62.83
632.24
3141592.65

36 人解决,40 人已尝试。

41 份提交通过,共有 54 份提交。

2.8 EMB 奖励。

创建: 12 年,11 月前.

修改: 2 年,10 月前.

最后提交: 3 月,1 周前.

来源: Ulm Local 1996

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