#include<bits/stdc++.h>
using namespace std;
int t, c;
int main()
{
int a[5], t; char q, w, e, r;
string s;
cin >> t;
while (t--)
{
memset(a, 0, sizeof(a));
cin >> s;
printf("case #%d:\n", c++);
for (int i = 0; i < s.size(); i++)
if (s[i] == '!')
a[i % 4]++;
else
s[i] == 'R' ? q = i : s[i] == 'B' ? w = i : s[i] == 'Y' ? e = i : r = i;
printf("%d %d %d %d\n", a[q % 4], a[w % 4], a[e % 4], a[r % 4]);
}
}
3188. 坏掉的彩灯
帕秋莉_诺蕾姬
hyf347347
其余实现起来都是常规思想，主要第三个测试点考察的是某一个全是感叹号的情况 如：R!YGR!YGR!YG
include
include
include
using namespace std;
int main()
{
int t;
int a[4];
cin >> t;
for (int i = 0; i < t; i++){
string s;
cin >> s;
memset(a, 0, sizeof(a));
int r=s.size(), b=s.size(), y=s.size(), g=s.size();
for (int k = 0; k < s.size(); k++){
if (s[k] == ‘!’){
a[k % 4]++;
}
else if (s[k] == ‘R’){
r = k;
}
else if (s[k] == ‘B’){
b = k;
}
else if (s[k] == ‘Y’){
y = k;
}
else if (s[k] == ‘G’){
g = k;
}
}
cout << “case #” << i << “:” << endl;
if (r<s.size()) cout << a[r % 4] << ” “;
else cout << a[6 - b % 4 - y % 4 - g % 4] << ” “;
if (b<s.size()) cout << a[b % 4] << ” “;
else cout << a[6 - r % 4 - y % 4 - g % 4] << ” “;
if (y<s.size()) cout << a[y % 4] << ” “;
else cout << a[6 - b % 4 - r % 4 - g % 4] << ” “;
if (g<s.size()) cout << a[g % 4] << endl;
else cout << a[6 - b % 4 - y % 4 - r % 4] << endl;
}
return 0;
}
四个的时候需要特判
大佬……