Difference between revisions of "CCPC-Final 2018"
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Solved by kblack. 01:31 (+) | Solved by kblack. 01:31 (+) | ||
+ | |||
+ | 题意:骑士站边,贡献不同,有些其实合不拢,求最大值与最小值差的最小值。 | ||
+ | |||
+ | 题解:先并查集求出所有联通块的站边方案,然后二分差值,把所有骑士分身两边后排序,滑动窗口划过去,判断所有联通块是否有机会全部满足。 | ||
== Problem D == | == Problem D == |
Revision as of 15:27, 25 November 2018
Replay
ultmaster:
- 两小时就结束了。
Problem A
Solved by zerol. 00:14 (+)
Problem B
Solved by kblack. 01:31 (+)
题意:骑士站边,贡献不同,有些其实合不拢,求最大值与最小值差的最小值。
题解:先并查集求出所有联通块的站边方案,然后二分差值,把所有骑士分身两边后排序,滑动窗口划过去,判断所有联通块是否有机会全部满足。
Problem D
Unsolved. (-3)
ultmaster: 代码相当宏伟。
Problem G
Solved by ultmaster. 00:29 (+1)
Problem H
博弈真好玩。
Problem I
Solved by zerol. 01:51 (+)
Problem K
Solved by kblack. 00:29 (+1)
题意:破解 RSA,离散数学期中考试题。
题解:暴力破出 $n=pq$,求个幂,指数是 $2^{30}+3$ 对 $\phi(n) = (p-1)(q-1)$ 的逆元。
Problem L
Solved by ultmaster. 00:55 (+)