Difference between revisions of "ITMO Chinese Winter Camp -Day4"
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Upsolved by Xiejiadong. (-8) | Upsolved by Xiejiadong. (-8) | ||
| − | 题意：求$i_1,i_2\cdots i_k$满足$1\le i_1<i_2<\cdots <i_k\le n$，且使得$max{(w_{i_1}+w_{i_2}),(w_{i_2}+w_{i_3},\cdots ,(w_{i_k}+w_{i_1}))}$最小。 | + | 题意：求$i_1,i_2\cdots i_k$满足$1\le i_1<i_2<\cdots <i_k\le n$，且使得$max{(w_{i_1}+w_{i_2}),(w_{i_2}+w_{i_3}),\cdots ,(w_{i_k}+w_{i_1}))}$最小。 |
题解： | 题解： | ||
Revision as of 11:53, 24 January 2019
ITMO Chinese Winter Camp Day4
Problem A
Solved by Xiejiadong. 00:19:49(+)
题意：求$B_1$进制下位数为$D_1$和$B_2$进制下位数为$D_2$的数一共有几个。
题解：求两个进制下位数为$D$的范围，取个交就好了。但要注意可能会爆long long，用除法来比较就不会出问题了。
Problem B
Solved by Kilo. 00:12:01(+1)
Problem C
Solved by Weaver_zhu. 00:10:53(+)
Problem D
Solved by Kilo. 00:43:10(+1)
Problem E
Solved by Kilo && Weaver_zhu. 04:10:23(+)
Problem F
Solved by Xiejiadong. 02:42:20(+3)
题意：每个物品只有一件，求放到背包里再也装不下东西的方案有多少。
题解：枚举正好塞不下的物品是哪一件，即剩下不拿的物品里面最小的物品是哪一件。
这样的话，比这个物品小的，肯定全部要塞下去，剩下比他大的物品，再背一遍0/1背包。
有个坑点就是，所有的物品都放下了，背包还是没有溢出，按照题意，这算是一种方案。
Problem G
Unsolved.
Problem H
Upsolved by Xiejiadong. (-8)
题意：求$i_1,i_2\cdots i_k$满足$1\le i_1<i_2<\cdots <i_k\le n$，且使得$max{(w_{i_1}+w_{i_2}),(w_{i_2}+w_{i_3}),\cdots ,(w_{i_k}+w_{i_1}))}$最小。
题解：
Problem I
Solved by Kilo. 01:50:23(+2)
Problem J
Unsolved.
Problem K
Unsolved.