2017 China Collegiate Programming Contest Final (CCPC2017)
Problem A
Solved by dreamcloud.00:08:07
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Problem B
Unsolved.
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Problem C
Solved by oxx1108.00:33:54(-2)
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Problem D
Unsolved.
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Problem E
Solved by dreamcloud.00:18:27
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Problem F
Unsolved.
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Problem G
Solved by oxx1108.02:24:42(-1)
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Problem H
Unsolved.
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Problem I
开这道题目仅仅是因为清晰度极高的图片吸引了我。
Solved by Xiejiadong.04:53:38(-4)
题意:联通且颜色相同的边算作一组,会有$m$次修改,求每一次修改以后的组数。
题解:我们用$f[i]$表示结点$i$连出去的边所拥有的颜色数量,因为直接$\sum f[i]$会有$n$条边重复计算,所以一个图上的总的组数就是$\sum f[i]-n$
但是应该很容易的注意到一种特殊情况:当基环树环上的颜色相同时,我们应该把答案变成$\sum f[i]-n+1$
这样一来,我们就可以直接在线处理了
PS:dfs中要用来遍历路径的迭代器开成了全局变量,一口巨锅飞向cmy
Problem J
Solved by Xiejiadong.03:59:12
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Problem K
Solved by Xiejiadong.00:15:55
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