Difference between revisions of "2018 Multi-University, Nowcoder Day 4"

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Upsolved by kblack.
 
Upsolved by kblack.
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题意:一堆概率出现的点,求在任意点左下角的点数的期望。
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题解:记录不在任意点左下角的概率,每个点相当于对一个矩形乘以 $(1-p)$,扫描线+线段树即可。
  
 
== Problem F ==
 
== Problem F ==

Revision as of 11:06, 28 July 2018

Problem A

Solved by zerol. 02:17 (+2)

Problem B

Problem C

Solved by ultmaster. 02:57 (+1)

Problem D

Solved by zerol. 01:19 (+1)

Problem E

Upsolved by kblack.

题意:一堆概率出现的点,求在任意点左下角的点数的期望。

题解:记录不在任意点左下角的概率,每个点相当于对一个矩形乘以 $(1-p)$,扫描线+线段树即可。

Problem F

Solved by ultmaster. 00:37 (+)

Problem G

Solved by kblack. 00:39 (+)

枚举即可,温暖的规律签到。

Problem H

Problem I

Problem J

Solved by kblack. 04:05 (+8)

题意:naive 的 hash 函数,naive 的解决方法(往后放),给出结果,求字典序最小的原插入顺序。

题解:很明显的拓扑排序,原题解是线段树优化。也可以考察特殊条件,所有相交的区间合并,包含的区间只会被跳一次,瞎几把搞一搞就好了,注意无解的判断即可。