单点时限: 2.0 sec
内存限制: 256 MB
定义函数 transpose 转置一个 n 阶方阵。元素类型是 int。
//********** Specification of transpose **********
void transpose(void *a, int n)
/* PreCondition:
a is beginning address of a square matrix, n is the number of rows for the matrix, no more than 80.
PostCondition:
the matrix is transposed
*/
只需按要求写出函数定义，并使用给定的测试程序测试你所定义函数的正确性。
不要改动测试程序。
测试正确后，将测试程序和函数定义一起提交。
/***************************************************************/
/* */
/* DON'T MODIFY main function ANYWAY! */
/* */
/***************************************************************/
#define N 10
/********** Specification of transpose **********/
void Transpose(void *a, int n)
/* PreCondition:
a is beginning address of a square matrix, n is the number of rows for the matrix, no more than 80.
PostCondition:
the matrix is transposed
*/
{
}
/***************************************************************/
#include <stdio.h>
#include <stdlib.h>
int main()
{ int *a,n,i; scanf("%d",&n);
a=(int*)malloc(n*n*sizeof(int));
for (i=0;i<n*n;i++) scanf("%d",a+i);
Transpose(a,n);
for (i=0;i<n*n;i++)
{ printf("%d ",a[i]); if ((i+1)%n==0) printf("\n"); }
free(a);
return 0;
}